20+d^2-11d=0

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Solution for 20+d^2-11d=0 equation: 



20+d^2-11d=0

a = 1; b = -11; c = +20;
Δ = b2-4ac
Δ = -112-4·1·20
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{41}}{2*1}=\frac{11-\sqrt{41}}{2}
$


$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{41}}{2*1}=\frac{11+\sqrt{41}}{2}
$

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